Objective
To investigate the relationship between the
molality and the boiling point of a solution.
Hypothesis
In this type of experiments, when we use a
solution instead of a pure liquid it is more difficult to form a nice regular
structure. For this reason, we must cool the solution to a lower temperature in
order for it to freeze.
In other words, the more solute is added to the
solution, the lower the freezing point will be. In this experiment, we are
gradually adding grams of sugar to our water-sugar solution. According to the
theoretical background, the bigger is the mass of sugar we add to the solution,
the lower the freezing point should be.
Results Table
Mass of sugar in solution
(g)
|
Molality
(mol/kg)
|
Attempt 1 - Freezing point (oC)
|
Attempt 2 - Freezing point (oC)
|
Average freezing point (oC)
|
Change in freezing point compared to pure water (oC)
|
0
|
0
|
0
|
-0.6
|
-0.3
|
-0.3
|
0.5
|
0,2
|
-0.6
|
-0.8
|
-0.7
|
-0.7
|
1.0
|
0,4
|
-0.3
|
-0.1
|
-0.2
|
-0.2
|
1.5
|
0,8
|
-1.7
|
-1.7
|
-1.7
|
-1.7
|
2.0
|
1
|
-2.0
|
-2.2
|
-2.1
|
-2.1
|
2.5
|
1,4
|
-2.9
|
-2.5
|
-2.7
|
-2.7
|
Graph
Conclusion
Observing the previous graph we can see that,
in most cases, as the molality (mol/kg) increases, the freezing point decreases
(ºC). There is only one case in which the freezing point increases as the
molality increases: when m= 0,4 and f.p= -0,2. This could be due to an error
committed while carrying out the experiment.
Nevertheless, these results match completely
with the hypothesis and the theoretical background. According to these, the
more solute is added to a solution the more difficult it will be for it to
freeze. In other words, the bigger is the molality the more difficult it is for
the solution to create a regular structure and therefore it needs to be cooled
at a lower temperature.
This is exactly what has happened in this
experiment. As we have increased the molality from 0 to 1,4 mol/kg, the
freezing point has also gradually decreased from -0,3 to -2,7 ºC. This is
clearly observable in the graph above, where the line goes down along the Y
axis (freezing point) as we go along the X axis (molality).
Evaluation
The first possible error is that, as we were
using an ice bath to cool down the solutions, we weren’t able to control the
temperature very well. The temperature varied as the time went onbecuase the
ice melted and, consequently, the water started to warm up. A solution to this
problem could be to have a separate ice bath for each experiment. This way, we
wouldn’t need the ice to be frozen for so long. This would provide us with more
controlled temperatures.
Another error that may have occurred is that we
didn’t really know when the solution had actually frozen because the
thermometer was inside the test tube and as it could move, we thought that it
was still liquid. This might have given us unreliable results. A solution to
this would be to check if the solution has frozen with a thin and long wooden
stick that we could introduce in the test tube.
References
-
Hyperphysics.phy-astr.gsu.edu,. (2015). Freezing Point Depression in
Solutions. Retrieved 21 February 2015, from http://hyperphysics.phy astr.gsu.edu/hbase/chemical/meltpt.html
-
Hyperphysics.phy-astr.gsu.edu,. (2015). Freezing Point Depression in
Solutions. Retrieved 21 February 2015, from
http://hyperphysics.phy-astr.gsu.edu/hbase/chemical/meltpt.html
-
Chemistryexplained.com,. (2015). Colligative Properties - Chemistry
Encyclopedia - water, uses, examples, gas, number, equation, salt, property.
Retrieved 21 February 2015, from
http://www.chemistryexplained.com/Ce-Co/Colligative-Properties.html
I would have liked to see you use the FP depression equation to support your hypothesis.
ResponderEliminarTables should be given a title.
The graph title could also be clearer and remember when we are investigating patterns then we must use a line of best fit and not a dot-to-dot line.
To improve your conclusion you could have compared your results with the theoretical results (using the equation and molality values).
You have identified 2 relevant problems but coudl have used a little more detail in explain how they would affect your results.
5/8 --> 6.3